The relation between time $t$ and distance $x$ of a particle is $t=a x^2+b x$, where $a$ and $\mathrm{b}$ are constants. If $\mathrm{v}$ is the velocity of the particle, then its acceleration is

• A

  $-2abv^2$
• B

  $2bv^3$
• Correct answer
  C

  $-2av^3$
• D

  $2av^2$

Hence, the correct answer is option: 'C'.