Q122 / 150 · MHT CET 2020 (14 Oct Shift 1) · Physics

The refractive index of the medium is $\mu=\mathrm{A}+\frac{\mathrm{B}}{\lambda^{2}}$, where $\mathrm{A}$ and $\mathrm{B}$ are constants and $\lambda$ is the wavelength of light. The dimensions of $B$ are same as that of

  • A
    Velocitv.
  • Correct answer
    B
    area.
  • C
    wavelength.
  • D
    Volume.

Solution

$\mu=\mathrm{A}+\frac{\mathrm{B}}{\lambda^{2}}$. Equating dimensions give $\frac{\mathrm{B}}{\lambda^{2}}=\mathrm{M}^{0} \mathrm{~L}^{0} \mathrm{~T}^{0}$ $\Rightarrow \mathrm{B}=\mathrm{M}^{0} \mathrm{~L}^{2} \mathrm{~T}^{0} \rightarrow$ same as dimension of area.

Hence, the correct answer is option: 'B'.

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