The reaction of t-butyl chloride and sodium ethoxide gives mainly

• A

  t-butyl ethyl ether
• B

  2,2-dimethylbutane
• Correct answer
  C

  2-methylprop-1-ene
• D

  isopropyl n-propyl ether

Solution

Sodium ethoxide is a strong base. The nucleophile $\mathrm{O}{\mathrm{C}}_2{\mathrm{H}}_5$ cannot attack at the carbon of bond due to steric hindrance. Hence, elimination reaction occurs to form alkene.

Hence, the correct answer is option: 'C'.