Q28 / 180 · KCET 2019 · Chemistry

The reaction in which \( \Delta \mathrm{H}>\Delta \mathrm{U} \) is

  • A
    \( \mathrm{N}_{2(g)}+3 \mathrm{H}_{2(g)} \rightarrow 2 \mathrm{NH}_{3(g)} \)
  • B
    \( \mathrm{CH}_{4(g)}+\mathrm{O}_{2(g)} \rightarrow \mathrm{CO}_{2(g)}+2 \mathrm{H}_{2} \mathrm{O}_{(l)} \)
  • C
    \( \mathrm{N}_{2(g)}+\mathrm{O}_{2(g)} \rightarrow 2 \mathrm{NO}_{2(g)} \)
  • Correct answer
    D
    \( \mathrm{CaCO}_{3(S)} \rightarrow \mathrm{CaO}_{(s)}+\mathrm{CO}_{2(g)} \)

Solution

(D)
\[ \begin{array}{l} \mathrm{CaCO}_{3(S)} \rightarrow \mathrm{CaO}_{(s)}+\mathrm{CO}_{2(g)} \\ \Delta \mathrm{n}=+1 \\ \Delta \mathrm{H}=\Delta \mathrm{U}+\Delta \mathrm{ngRT} \end{array} \]

Hence, the correct answer is option: 'D'.

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