The reaction A_2+B_2 arrow 2 AB follows the mechanism The overall order of the reaction is :

Correct answer: (D) 1.5. rate =k_2[~A] [B_2 ] … … (frack_1k_-1 )= (([A]^2)/([~A_2 ]) ) ⇒[A]=√frack_1k_-1 · √([~A_2 ]) Substituting in (1) ; we get Rate =k_2 √frack_1k_-1 · [~A_2 ]^1/2 · [~B_2 ] ∴ order = (3/2 )=1.5

Q14 / 75 · JEE Main 2025 (29 Jan Shift 1) · Chemistry

The reaction $\mathrm{A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{AB}$ follows the mechanism The overall order of the reaction is :

A
2
B
2.5
C
3
Correct answer
D
1.5

Solution

$\begin{aligned} & \text { rate }=\mathrm{k}_2[\mathrm{~A}]\left[\mathrm{B}_2\right] \ldots \ldots \\ & \left(\frac{\mathrm{k}_1}{\mathrm{k}_{-1}}\right)=\left(\frac{[\mathrm{A}]^2}{\left[\mathrm{~A}_2\right]}\right) \\ & \Rightarrow[\mathrm{A}]=\sqrt{\frac{\mathrm{k}_1}{\mathrm{k}_{-1}}} \cdot \sqrt{\left[\mathrm{~A}_2\right]} \end{aligned}$ Substituting in (1) ; we get $\begin{aligned} & \text { Rate }=\mathrm{k}_2 \sqrt{\frac{\mathrm{k}_1}{\mathrm{k}_{-1}}} \cdot\left[\mathrm{~A}_2\right]^{\frac{1}{2}} \cdot\left[\mathrm{~B}_2\right] \\ & \therefore \text { order }=\left(\frac{3}{2}\right)=1.5\end{aligned}$

Hence, the correct answer is option: 'D'.

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The reaction \(\mathrm{A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{AB}\) follows the mechanism The overall order of the reaction is :

Solution

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