Q109 / 150 · MHT CET 2024 (15 May Shift 1) · Physics

The ratio of work done by an ideal rigid diatomic gas to the heat supplied by the gas in an isobaric process is

  • A
    $\frac{3}{7}$
  • Correct answer
    B
    $\frac{2}{7}$
  • C
    $\frac{4}{7}$
  • D
    $\frac{5}{7}$

Solution

For an isobaric process, $\begin{array}{ll} & \frac{\Delta \mathrm{Q}}{\Delta \mathrm{U}}=\frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{v}}}=\frac{7}{5} \\ \therefore \quad & \frac{\Delta \mathrm{Q}-\Delta \mathrm{U}}{\Delta \mathrm{Q}}=\frac{7-5}{7} \quad \text { (Applying dividendo) } \\ \therefore \quad & \frac{\mathrm{W}}{\Delta \mathrm{Q}}=\frac{2}{7} \end{array}$

Hence, the correct answer is option: 'B'.

Relevant Questions