Q13 / 90 · JEE Main 2019 (10 Apr Shift 2) · Chemistry

The ratio of the shortest wavelength of two spectral series of hydrogen spectrum is found to be about $9$ . The spectral series are:

A
Paschen and Pfund
B
Balmer and Brackett
Correct answer
C
Lyman and Paschen
D
Brackett and Pfund

Solution

\frac{\frac{1}{λ_{2}} = R_{H} (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}})}{\frac{1}{λ_{1}} = R_{H} (\frac{1}{m_{1}^{2}} - \frac{1}{m_{2}^{2}})}

As for shortest wavelengths,

n_{2}

and

m_{2}

is

\infty

.

∴ \frac{λ_{1}}{λ_{2}} = \frac{9}{1} = \frac{m_{1}^{2}}{n_{1}^{2}}

Now if

m_{1} = 3

and

n_{1} = 1

it will justify the statement hence Lyman and Paschen

(B)

is correct.

Hence, the correct answer is option: 'C'.

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