Q85 / 120 · VITEEE 2019 · Physics

The ratio of the energies of the hydrogen atom in its first to second excited states is

  • A
    $1 / 4$
  • B
    $4 / 9$
  • Correct answer
    C
    $9 / 4$
  • D
    4

Solution

Ist excited state corresponds to $\mathrm{n}=2$ 2nd excited state corresponds to $\mathrm{n}=3$ As $E \propto \frac{1}{n^{2}}$ $$ \therefore \quad \frac{\mathrm{E}_{1}}{\mathrm{E}_{2}}=\frac{\mathrm{n}_{2}^{2}}{\mathrm{n}_{1}^{2}}=\frac{3^{2}}{2^{2}}=\frac{9}{4} $$

Hence, the correct answer is option: 'C'.

Relevant Questions