Q128 / 150 · MHT CET 2017 · Physics

The ratio of the binding energy of a satellite at rest on earth's surface to the binding energy of a satellite of same mass revolving around the earth at a height h above the earth's surface is (R= radius of the earth).

  • A
    2(R+h)R
  • B
     R+h2R
  • Correct answer
    C
    R+hR
  • D
    RR+h

Solution

Binding energy on the surface of the earth
E1=GMm2R
Binding energy of revolving satellite
E2=GMm2(R+h)
∴    E1E2=(R+h)R    

Hence, the correct answer is option: 'C'.

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