Q170 / 180 · COMEDK 2023 (Morning Shift) · Physics
The ratio of amplitude of magnetic field to the amplitude of electric field of an electromagnetic wave propagating in vacuum is
- Ainversely proportional to the frequency of the electromagnetic wave
- Bthe speed of light in vacuum
- Cproportional to frequency of the electromagnetic wave
- Correct answerDreciprocal of speed of light in vacuum
Solution
For an electromagnetic wave propagating in vacuum, the relationship between the amplitude of the electric field $E_0$ and the amplitude of the magnetic field $B_0$ is given by the equation $E_0 = c B_0$, where $c$ is the speed of light in vacuum.
The ratio of the amplitude of the magnetic field to the amplitude of the electric field is $\dfrac{B_0}{E_0} = \dfrac{1}{c}$.
Since $c = \dfrac{1}{\sqrt{\mu_0 \epsilon_0}}$, the ratio $\dfrac{B_0}{E_0}$ is the reciprocal of the speed of light in vacuum.
Answer: reciprocal of speed of light in vacuum
The ratio of the amplitude of the magnetic field to the amplitude of the electric field is $\dfrac{B_0}{E_0} = \dfrac{1}{c}$.
Since $c = \dfrac{1}{\sqrt{\mu_0 \epsilon_0}}$, the ratio $\dfrac{B_0}{E_0}$ is the reciprocal of the speed of light in vacuum.
Answer: reciprocal of speed of light in vacuum
Hence, the correct answer is option: 'D'.