Q42 / 170 · Manipal (MET) 2021 · Chemistry

The rate of a gaseous reaction is given by the expression $k[A][B]$. If the volume of the reaction vessel is suddenly reduced to $1 / 4$ th of the initial volume, the reaction rate relating to original rate will be :

  • A
    $\frac{1}{10}$
  • B
    $\frac{1}{8}$
  • C
    8
  • Correct answer
    D
    16

Solution

On reducing the volume $\frac{1}{4}$ th of the initial volume, each concentration will be increased by 4 times. $\begin{aligned}(\text { Rate })_1 & =k[A][B] \\ (\text { Rate })_2 & =k[4[\mathrm{~A}][4[\mathrm{~B}]]\end{aligned}$ Hence, $\frac{[\text { Rate }]_2}{[\text { Rate }]}=4 \times 4=16$

Hence, the correct answer is option: 'D'.

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