Q19 / 160 · TS EAMCET 2006 · Chemistry

The rate constant of a first order reaction at $27^{\circ} \mathrm{C}$ is $10^{-3} \mathrm{~min}^{-1}$. The temperature coefficient of this reaction is 2 . What is the rate constant (in $\mathrm{min}^{-1}$ ) at $17^{\circ} \mathrm{C}$ for this reaction?

  • A
    $10^{-3}$
  • Correct answer
    B
    $5 \times 10^{-4}$
  • C
    $2 \times 10^{-3}$
  • D
    $10^{-2}$

Solution

Temperature coefficient, $=\frac{k_t+10}{k_t}$ $2=\frac{10^{-3}}{k_t}$ $k_t=\frac{10^{-3}}{2}=\frac{10 \times 10^{-4}}{2}=5 \times 10^{-4}$

Hence, the correct answer is option: 'B'.

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