Q7 / 90 · KVPY 2015 (SB/SX) · Chemistry
The rate constant of a chemical reaction at a very high temperature will approach
- AArrhenius frequency factor divided by the ideal gas constant
- BActivation energy
- Correct answerCArrhenius frequency factor
- Dactivation energy divided by the ideal gas constant
Solution
$\mathrm{k}=\mathrm{Ae}^{-\mathrm{E} / \mathrm{RT}} ;
\quad$At$\mathrm{T} \rightarrow \infty ; \mathrm{k}=\mathrm{Ae}^{-\mathrm{E}_{\mathrm{A}}[\mathbb{R} \times \infty]}=\mathrm{Ae}^{0}$
$\mathrm{~K}=\mathrm{A}$
Hence, the correct answer is option: 'C'.