Q24 / 90 · JEE Main 2017 (02 Apr) · Chemistry

The radius of the second Bohr orbit for hydrogen atom is

(Planck's constant, (h)=6.6262×10−34Js; mass of electron =9.1091×10-31kg; charge of electron =1.60210×10-19C; permittivity of vacuum, (∈0)=8.854185×10-12kg-1m-3A2)

  • A
    4.76 Å
  • B
    0.529 Å
  • Correct answer
    C
    2.12 Å
  • D
    1.65 Å

Solution

Radius of the Bohr's orbit is calculated by the following formula rn=0.529×n2zÅ

Radius is directly proportional to square of nth orbit and inversely proportional to atomic number. This formula works for single electron species

here rn=radius of the nth orbit

Z=1 and n=orbit or shell number

r2=0.529×221 Å

=2.12 Å

 

Hence, the correct answer is option: 'C'.

Relevant Questions