Q156 / 160 · TS EAMCET 2023 (13 May Shift 2) · Physics
The radius of nucleus of mass number 27 is $R$. Which of the following is true about a nucleus whose radius is $2 \mathrm{R}$ ?
- Correct answerAIt is stable in nature
- BIts mass number is 54
- CIt is likely to undergo fission reaction
- DIt is likely to undergo fusion reaction
Solution
$\begin{aligned}
& \text {} \frac{R_1}{R_2}=\left(\frac{A_1}{A_2}\right)^{1 / 3} \\
& R_1=R, R_2=2 R A_1=27 \\
& \frac{R}{2 R}=\left(\frac{27}{A_2}\right)^{1 / 3} \Rightarrow \frac{-}{8}=\frac{}{A_2} \\
& A_2=216
\end{aligned}$
It is stable in nature.
Hence, the correct answer is option: 'A'.