Q69 / 200 · NEET 2004 · Chemistry

The radioactive isotope ${ }_{27}^{60} \mathrm{Co}$ which is used in the treatment of cancer can be made by $(n, p)$ reaction. For this reaction the target nucleus is:

A
${ }_{28}^{59} \mathrm{Ni}$
B
${ }_{27}^{59} \mathrm{Co}$
Correct answer
C
${ }_{28}^{60} \mathrm{Ni}$
D
${ }_{27}^{60} \mathrm{Co}$

Solution

${ }_{28}^{60} \mathrm{Ni}+{ }_0 n^1 \longrightarrow{ }_{27}^{60} \mathrm{Co}+{ }_1^1 \mathrm{P}$ Related Theory Cobalt therapy is the medical use of gamma rays from the radioisotope cobalt-60 to treat cancer. Caution $(n, p)$ means that neutron attacks and proton liberated respectively.

Hence, the correct answer is option: 'C'.

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