Q25 / 160 · TS EAMCET 2003 · Chemistry

The product obtained at anode when $50 \%$ $\mathrm{H}_2 \mathrm{SO}_4$ aqueous solution is electrolysed using platinum electrodes is :

  • A
    $\mathrm{H}_2 \mathrm{SO}_3$
  • Correct answer
    B
    $\mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_8$
  • C
    $\mathrm{O}_2$
  • D
    $\mathrm{H}_2$

Solution

$50 \% \mathrm{H}_2 \mathrm{SO}_4$ aqueous solution can be electrolysed by using Pt electrodes as $2 \mathrm{H}_2 \mathrm{SO}_4 2 \mathrm{HSO}_4^{-}+2 \mathrm{H}^{+}$ $2 \mathrm{HSO}_4^{-} \longrightarrow \mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_8+2 e^{-}$(at anode)

Hence, the correct answer is option: 'B'.

Relevant Questions