Q14 / 75 · JEE Main 2020 (04 Sep Shift 2) · Chemistry

The process that is NOT endothermic in nature is :

A
${Ar}_{(g)} + e^{-} \to {Ar}_{(g)}^{-}$
Correct answer
B
$H_{(g)} + e^{-} \to H_{(g)}^{-}$
C
$O_{(g)}^{-} + e^{-} \to O_{(g)}^{2 -}$
D
${Na}_{(g)} \to {Na}_{(g)}^{+} + e^{-}$

Solution

$H_{(g)} {+e}^{-} \overset{extremic}{\to} {H^{-}}_{(g)}$	${ΔH}_{eg} = - 72 KJ / mol$
$O^{-} (g) + e^{-} ⟶ \overset{endeterm c}{\to} O^{2 -} (g)$	${ΔH}_{eg} = + 744 KJ / mol$
${Ar}_{(g)} + e^{-} \overset{endeterm c}{\to} {Ar}^{-} (g)$	${ΔH}_{eg} = + 96 KJ / mol$
$Na (g) \overset{endotherm c}{⟶} {Na}^{+} (g) + e^{-}$	$IE = 495.8 KJ / mol$

Hence, the correct answer is option: 'B'.

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