Q41 / 108 · NTA Abhyas (JEE Main) 2020 · Mathematics · Probability

The probability distribution of a random variable X is given as
 
X −5 −4 −3 −2 −1 0 1 2 3 4 5
P( X ) p 2p 3p 4p 5p 7p 8p 9p 10p 11p 12p

Then, the value of p is

  • Correct answer
    A
    172
  • B
    373
  • C
    572
  • D
    174

Solution

Sum of Probabilities =1

⇒ p+2p+3p+4p+5p+7p+8p+9p+10p+11p+12p=1

⇒72p=1⇒p= 1 72

Hence, the correct answer is option: 'A'.

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