Q139 / 160 · TS EAMCET 2010 · Physics

The potential difference between two parallel plates is $10^4 \mathrm{~V}$. If the plates are separated by $0.5 \mathrm{~cm}$, the force on an electron between the plates is

  • A
    $32 \times 10^{-13} \mathrm{~N}$
  • B
    $0.32 \times 10^{-13} \mathrm{~N}$
  • C
    $0.032 \times 10^{-13} \mathrm{~N}$
  • Correct answer
    D
    $3.2 \times 10^{-13} \mathrm{~N}$

Solution

The force $F=\frac{e V}{d}$ $=\frac{1.6 \times 10^{-19} \times 10^4}{0.5 \times 10^{-2}}$ $=3.2 \times 10^{-13} \mathrm{~N}$

Hence, the correct answer is option: 'D'.

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