The position vectors of two points A and B are $\bar{i}+2 \bar{j}+3 \bar{k}$ and $7 \bar{i}-\bar{k}$ respectively. The point P with position vector $-2 \bar{i}+3 \bar{j}+5 \bar{k}$ is on the line AB. If the point Q is the harmonic conjugate of P, then the sum of the scalar components of the position vector of Q is

• Correct answer
  A

  $6$
• B

  $4$
• C

  $2$
• D

  $0$

Hence, the correct answer is option: 'A'.