The position vector of a particle is $\overrightarrow{r}=\left(3\hat{\mathrm{i}}+4\hat{\mathrm{j}}\right) \mathrm{metre}$ and its angular velocity $\overrightarrow{\omega }=\left(\hat{\mathrm{j}}+2\hat{\mathrm{k}}\right) \mathrm{rad} {\mathrm{s}}^{-1}$  then its linear velocity is $\left(\mathrm{i}\mathrm{n}\mathrm{ }\mathrm{m} {\mathrm{s}}^{-1}\right)$

• Correct answer
  A

  $-\left(8\hat{\mathrm{i}}-6\hat{\mathrm{j}}+3\hat{\mathrm{k}}\right)$
• B

  $\left(3\hat{\mathrm{i}}+6\hat{\mathrm{j}}+8\hat{\mathrm{k}}\right)$
• C

  $-\left(3\hat{\mathrm{i}}+6\hat{\mathrm{j}}+6\hat{\mathrm{k}}\right)$
• D

  $\left(6\hat{\mathrm{i}}+8\hat{\mathrm{j}}+3\hat{\mathrm{k}}\right)$

Hence, the correct answer is option: 'A'.