The position vector of a particle is determined by the expression r→=2t^2i^+3tj^+9k^. The magnitude of its displacement (in m) in first two seconds is

Question

MARKS Content Team · Accepted Answer

Correct answer: 10. r→=2t^2i^+3tj^+9k^ At t=0,r_1→=9k^ At t=2s,r_2→=8i^+6j^+9k^ ∴ Δr→=r_2→-r_1→=8i^+6j^ ∴Δr→=r_2→-r_1→=√(8^2+6^2)=10m

The position vector of a particle is determined by the expression $\vec{r} = 2 t^{2} \hat{i} + 3 t \hat{j} + 9 \hat{k}$ . The magnitude of its displacement (in $m$ ) in first two seconds is

Solution

More Motion In Two Dimensions Questions

The position vector of a particle is determined by the expression r→=2t2i^+3tj^+9k^. The magnitude of its displacement (in m) in first two seconds is

Solution

More Motion In Two Dimensions Questions

The position vector of a particle is determined by the expression $\vec{r} = 2 t^{2} \hat{i} + 3 t \hat{j} + 9 \hat{k}$ . The magnitude of its displacement (in $m$ ) in first two seconds is