Q130 / 150 · MHT CET 2025 (26 Apr Shift 2) · Physics

The plot of magnetic flux ' $\phi$ ' linked with the coil versus current ' $I$ ' is as shown in figure for two inductors $L_1$ and $L_2$. The self inductance of Figure

  • A
    $\mathrm{L}_1$ is equal to that of $\mathrm{L}_2$.
  • B
    $L_1$ is less than that of $L_2$.
  • Correct answer
    C
    $L_1$ is greater than that of $L_2$.
  • D
    $L_1$ is half that of $L_2$.

Solution

The magnetic flux $\phi$ through a coil relates to the current $I$ by $\phi = LI$, where $L$ denotes the self-inductance. On a $\phi$ vs. $I$ graph, this is a linear equation of the form $y = mx$, so the slope corresponds to $L$.

Since the line for $L_1$ is steeper than that for $L_2$, its slope—and thus its self-inductance—is greater. Therefore, $L_1 > L_2$.

The correct choice is $\boxed{C}$.

Hence, the correct answer is option: 'C'.

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