The pitch of the screw gauge is $1 \mathrm{mm}$ and there are $100$ divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lies $8$ divisions below the reference line. When a wire is placed between the jaws, the first linear scale division is clearly visible while ${72}^{\text{nd }}$ division on circular scale coincides with the reference line. The radius of the wire is

• A

  $1.64 \mathrm{mm}$
• Correct answer
  B

  $0.82 \mathrm{mm}$
• C

  $0.90 \mathrm{mm}$
• D

  $1.80 \mathrm{mm}$

Hence, the correct answer is option: 'B'.