Q83 / 90 · JEE Main 2019 (09 Jan Shift 2) · Physics

The pitch and the number of divisions, on the circular scale, for a given screw gauge are 0.5 mm and 100 respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line.

The readings of the main scale and the circular scale, for a thin sheet, are 5.5 mm and 48 respectively, the thickness of this sheet is:

  • A
    5.755 mm
  • B
    5.740 mm
  • Correct answer
    C
    5.725 mm
  • D
    5.950 mm

Solution

least count =0.5 mm100=0.005 mm

Reading =5.5 mm+48-3×0.005 mm

=5.725 mm.

Hence, the correct answer is option: 'C'.

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