Q20 / 109 · NTA Abhyas (JEE Main) 2020 · Mathematics · Straight Lines

The perpendicular bisector of the line segment joining A1,4 and Bt,3 has y-intercept equal to -4. Then, the product of all possible values of t is equal to

  • A
    1
  • B
    2
  • Correct answer
    C
    -16
  • D
    -4

Solution

The slope of the perpendicular bisector =t-1
The mid-point of the line segment =t+12,72
∴ Equation of the bisector is y-72=t-1x-t+12
Putting x=0 and y=-4, we get,

t=±4

Hence, the required product =4-4=-16

Hence, the correct answer is option: 'C'.

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