Q123 / 150 · MHT CET 2021 (23 Sep Shift 1) · Physics

The period of revolution of planet A around the sun is 8 times that of planet B. How many times the distance of A from the sun is greater than that of B from the sun?

  • A
    5 times
  • B
    2 times
  • Correct answer
    C
    3 times
  • D
    6 times

Solution

$\begin{aligned} & \left(\frac{\mathrm{R}_1}{\mathrm{R}_2}\right)^3=\left(\frac{\mathrm{T}_1}{\mathrm{~T}_2}\right)^2=(8)^2=64 \\ & \therefore \frac{\mathrm{R}_1}{\mathrm{R}_2}=(64)^{\frac{1}{3}}=4 \\ & \therefore \mathrm{R}_1=4 \mathrm{R}_2 \\ & \therefore \mathrm{R}_1-\mathrm{R}_2=4 \mathrm{R}_2-\mathrm{R}_2=3 \mathrm{R}_2\end{aligned}$

Hence, the correct answer is option: 'C'.

Relevant Questions