The period of a simple pendulum inside a stationary lift is $T$. The lift accelerates upwards with an acceleration of $\frac{\mathrm{g}}{3}$. The time period of pendulum will be

• A

  $\sqrt{2}\mathrm{ }T$
• B

  $\frac{T}{\sqrt{2}}$
• Correct answer
  C

  $\frac{\sqrt{3}}{2}T$
• D

  $\frac{T}{3}$

Hence, the correct answer is option: 'C'.