Q47 / 180 · KCET 2012 · Chemistry

The percentage of $p$-character of the hybrid orbitals in graphite and diamond are respectively

  • A
    50 and 75
  • Correct answer
    B
    67 and 75
  • C
    33 and 75
  • D
    33 and 25

Solution

In graphite, C-atom is $\mathrm{sp}^{2}$ hybridised. $\therefore$ p-character $=\frac{2}{3} \times 100 \approx 67 \%$ Again in diamond, C-atom is $\mathrm{sp}^{3}$ hybridised. $\therefore$ p-character $=\frac{3}{4} \times 100=75 \%$

Hence, the correct answer is option: 'B'.

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