Q37 / 180 · KCET 2020 · Chemistry

The percentage of $s$-character in the hybrid orbitals of nitrogen in $\mathrm{NO}_{2}^{+}, \mathrm{NO}_{3}^{-}$respectively are

  • A
    $33.3 \%, 50 \%, 25 \%$
  • B
    $33.3 \%, 25 \%, 50 \%$
  • Correct answer
    C
    $50 \%, 33.3 \%, 25 \%$
  • D
    $25 \%, 50 \%, 33.3 \%$

Solution

$\mathrm{NO}_{2}^{+}$shows $s p$-hybridisation and as such the $s$-character here shall be $50 \%$. $\mathrm{NO}_{3}^{-}$shows $s p^{2}$ hybridisation, so the $s$-character shall be $33.3 \%$.

Hence, the correct answer is option: 'C'.

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