Q18 / 268 · NTA Abhyas (NEET) 2020 · Physics · Thermodynamics

The percentage change in internal energy, when a gas is cooled from $927 ° C$ to $27 ° C$ , is

Correct answer
A
$75 %$
B
$300 %$
C
$50 %$
D
$100 %$

Solution

Here,

T_{1} = 927 ℃ = (927 + 273) K = 1200 K

T_{2} = 27 ℃ = (27 + 273) K = 300 K

As

U \propto T

∴ \frac{∆ U}{U_{1}} = \frac{U_{1} - U_{2}}{U_{1}} = \frac{1200 - 300}{1200} \times 100 = 75 %

Hence, the correct answer is option: 'A'.

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