Q101 / 160 · JIPMER 2004 · Physics

The peak value of alternating current is $5 \sqrt{2}$ ampere. The mean square value of current will be

  • Correct answer
    A
    $5$ A
  • B
    $2.5$ A
  • C
    $5 \sqrt{2}$
  • D
    None of the above

Solution

Here: $I_0=5 \sqrt{2} \mathrm{~A}$ Root mean square value of current $I_{\mathrm{rms}}=\frac{I_0}{\sqrt{2}} = \frac{5 \sqrt{2}}{\sqrt{2}}=5 \mathrm{~A}$

Hence, the correct answer is option: 'A'.

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