Q2 / 90 · KVPY 2017 (19 Nov SB/SX) · Chemistry

The particle emitted during the sequential radioactive decay of ${ }^{238} \mathrm{U}_{92}$ to ${ }^{206} \mathrm{~Pb}_{82}$ are

  • A
    $5 \alpha$ and $6 \beta$
  • B
    $6 \alpha$ and $8 \beta$
  • C
    $8 \alpha$ and $4 \beta$
  • Correct answer
    D
    $8 \alpha$ and $6 \beta$

Solution

no of $\alpha$ particle $=\frac{238-206}{4}=8$ no of $\beta$-particle $=6$

Hence, the correct answer is option: 'D'.

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