The particle A is converted into C via the following reaction. A→B+ _2He^4 B→ C + 2e^(-) Then

Question

MARKS Content Team · Accepted Answer

Correct answer: (B) A and C are isotopes. Let x be the mass number of A and y the atomic number. Then , since atomic number and mass number remain conserved, we have _yA^x→ _(y-2)B^(x-4) + _2He^4 _(y-2)B^(x-4)→_yC^(x-4) + 2_(-1)e^0 Hence, we observe that A and C are isotopes as their atomic numbers are same but mass numbers are different.

The particle $A$ is converted into $C$ via the following reaction.
$A \to B +_{2} H e^{4}$
$B \to C + 2 e^{-}$
Then

Solution

More Nuclear Physics Questions

The particle A is converted into C via the following reaction. A→B+ 2He4 B→ C + 2e- Then

Solution

More Nuclear Physics Questions

The particle $A$ is converted into $C$ via the following reaction.
$A \to B +_{2} H e^{4}$
$B \to C + 2 e^{-}$
Then