Q31 / 180 · KCET 2014 · Chemistry
The pair of compounds having identical shapes for their molecules is
- A\( \mathrm{BCl}_{2}, \mathrm{ClF}_{3} \)
- B\( \mathrm{SO}_{2}, \mathrm{CO}_{2} \)
- C\( \mathrm{CH}_{4}, \mathrm{SF}_{4} \)
- Correct answerDNone of the above
Solution
Hybridization of \( \mathrm{Xe} \) in \( \mathrm{XeF}_{2} \) molecule is \( p^{3} d \) Three lone pair of electrons occupies the equatorial position and two \( \mathrm{F} \)
atoms occupies axial position therefore; its shape is linear \( \mathrm{ZnCl}_{2} \) is an ionic compound. So, non of the pair have
identical shape.
atoms occupies axial position therefore; its shape is linear \( \mathrm{ZnCl}_{2} \) is an ionic compound. So, non of the pair have
identical shape.
Hence, the correct answer is option: 'D'.