Q12 / 125 · BITSAT 2013 · Chemistry

The oxidation state of sulphur in $\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}$ is

  • A
    6
  • B
    $\frac{+3}{2}$
  • Correct answer
    C
    $\frac{+5}{2}$
  • D
    -2

Solution

$\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}$ $2+4 x-12=0$ $4 x-10=0$ $x=\frac{10}{4}=\frac{+5}{2}$ Oxidation state of $\mathrm{S}$ is $=\frac{+5}{2}$

Hence, the correct answer is option: 'C'.

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