Q53 / 180 · NEET 2019 (Odisha) · Chemistry
The oxidation state of $\mathrm{Cr}$ in $\mathrm{CrO}_5$ is
- A-6
- B+12
- Correct answerC+6
- D+4
Solution
$\text {The structure of } \mathrm{CrO}_5 \text { is }$
Oxidation state of $\mathrm{Cr}$ is +6 due to the presence of two peroxide linkages, which can be calculated as. In $\mathrm{CrO}\left(\mathrm{O}_2\right)_2$, let the oxidation state of $\mathrm{Cr}$ be $\mathrm{x}$ $\begin{aligned} \mathrm{x}+(-1) 4+(-2) & =0 \\ \mathrm{x}-6 & =0 \\ \mathrm{x} & =+6 \end{aligned}$
Oxidation state of $\mathrm{Cr}$ is +6 due to the presence of two peroxide linkages, which can be calculated as. In $\mathrm{CrO}\left(\mathrm{O}_2\right)_2$, let the oxidation state of $\mathrm{Cr}$ be $\mathrm{x}$ $\begin{aligned} \mathrm{x}+(-1) 4+(-2) & =0 \\ \mathrm{x}-6 & =0 \\ \mathrm{x} & =+6 \end{aligned}$
Hence, the correct answer is option: 'C'.