Q4 / 225 · JEE Main 2005 · Chemistry

The oxidation state of $\mathrm{Cr}$ in $\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]^{+}$is

  • Correct answer
    A
    $+3$
  • B
    $+2$
  • C
    $+1$
  • D
    0

Solution

$\left(\mathrm{Cr}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right)^{+}$ $X+4 \times 0+2 \times-1=1$ $\mathrm{X}=+3$

Hence, the correct answer is option: 'A'.

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