Q136 / 180 · NEET 2013 (All India) · Physics

The output $(X)$ of the logic circuit shown in figure will be Figure

  • A
    $X=\overline{\bar{A}} \cdot \overline{\bar{B}}$
  • B
    $X=\overline{A \cdot B}$
  • Correct answer
    C
    $X=A \cdot B$
  • D
    $X=\overline{A+B}$

Solution

$X=\overline{\overline{A B}}=A \cdot B$ (i.e., AND gate) If the output $X$ of NAND gate is connected to the input of NOT gate (made from NAND gate by joining two inputs) from the given figure then we get back an AND gate.

Hence, the correct answer is option: 'C'.

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