Q19 / 120 · VITEEE 2006 · Chemistry

The order of the reaction $\mathrm{N}_{2} \mathrm{O}_{5} \rightarrow \mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \mathrm{is}$

A
3
B
2
Correct answer
C
1
D
0

Solution

It is a first order reaction because rate of reaction $\propto\left[\mathrm{N}_{2} \mathrm{O}_{5}\right]$

Hence, the correct answer is option: 'C'.

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