Q27 / 225 · JEE Main 2003 · Chemistry

The orbital angular momentum for an electron revolving in an orbit is given by $\sqrt{l(l+1)} \cdot \frac{\mathrm{h}}{2 \pi}$. This momentum for an s-electron will be given by

Correct answer
A
zero
B
$\frac{\mathrm{h}}{2 \pi}$
C
$\sqrt{2} \cdot \frac{\mathrm{h}}{2 \pi}$
D
$+\frac{1}{2} \cdot \frac{\mathrm{h}}{2 \pi}$

Solution

For s-electron, $l=0 \quad \therefore$ angular momentum $=$ zero

Hence, the correct answer is option: 'A'.

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