Q50 / 180 · NEET 2019 (Odisha) · Chemistry

The $\mathrm{pH}$ of $0.01 \mathrm{M} \mathrm{NaOH}(a q)$ solution will be

  • A
    7.01
  • B
    2
  • Correct answer
    C
    12
  • D
    9

Solution

$\mathrm{NaOH}$ is a strong base, thus $$ \begin{aligned} {\left[\mathrm{OH}^{-}\right] } & =0.0 \mathrm{M}=10^{-2} \mathrm{M} \\ \mathrm{pOH} & =-\log \left[\mathrm{OH}^{-}\right]=-\log \left(10^{-2}\right)=2 \end{aligned} $$ We know that, $\mathrm{pH}+\mathrm{pOH}=14$ $\therefore \quad \mathrm{pH}=14-2=12$ Thus, option (3) is correct.

Hence, the correct answer is option: 'C'.

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