The objective function $Z=4x_1+5x_2,$ subject to $2x_1+x_2\ge 7, 2x_1+3x_2\le 15,x_2\le 3,x_1,x_2\ge 0$ has minimum value at the point

Value of \(\mathrm{z}=4 \mathrm{x}_{1}+5 \mathrm{x}_{2}\) Convert the given inequalities into equalities to get the corner points \(2 x_{1}+x_{2}=7 \ldots \ldots\) (i) At \(x_{1}=0, x_{2}=7\) and \(x_{2}=0, x_{1}=3.5\) So, the corner points of (i) are \((0,7)\) and \((3.5,0)\) \(2 \mathrm{x}_{1}+3 \mathrm{x}_{2}=15 \ldots \ldots\) (ii) At \(\mathrm{x}_{1}=0, \mathrm{x}_{2}=5\) and \(\mathrm{x}_{2}=0, \mathrm{x}_{1}=7.5\) So, the corner points of (i) are \((0,5)\) and \((7.5,0)\) \(\mathrm{x}_{2}=3\)..... (iii) Plot these corner points on the graph paper and the line given in (iii) The shaded part shows the feasible region. At \(x_{2}=3, x_{1}=2\) in (i) and \(x_{1}=3\) in (ii) The corner points of the feasible region are \((3.5,0),(7.5,0),(3,3)\) and \((2,3)\) Corner points \(Z=4 x_{2}+5 x_{2}\) \(\begin{array}{ll}(3.5,0) & 14 \\ (7.5,0) & 30 \\ (3,3) & 27 \\ (2,3) & 23\end{array}\) Minimum value of \(Z=14\) and it lies on \(x\)-axis.