The number of white coloured salts among the following is .......

$\left(\mathrm{A}\right) {\mathrm{SrSO}}_4 \left(\mathrm{B}\right) \mathrm{Mg}\left({\mathrm{NH}}_4\right){\mathrm{PO}}_4 \left(\mathrm{C}\right) {\mathrm{BaCrO}}_4$

$\left(\mathrm{D}\right) \mathrm{Mn}(\mathrm{OH}{)}_2 \left(\mathrm{E}\right) {\mathrm{PbSO}}_4 \left(\mathrm{F}\right) {\mathrm{PbCrO}}_4$

$\left(\mathrm{G}\right) \mathrm{AgBr} \left(\mathrm{H}\right) {\mathrm{PbI}}_2 \left(\mathrm{I}\right) {\mathrm{CaC}}_2{\mathrm{O}}_4$

$\left(\mathrm{J}\right) \left[\mathrm{Fe}(\mathrm{OH}{)}_2\left({\mathrm{CH}}_3\mathrm{COO}\right)\right]$

The colour of the salts are as follows,

${\mathrm{SrSO}}_4$- white
$\mathrm{Mg}\left({\mathrm{NH}}_4\right){\mathrm{PO}}_4$ - white
${\mathrm{BaCrO}}_4$ - yellow
$\mathrm{Mn}(\mathrm{OH}{)}_2$ - white
${\mathrm{PbSO}}_4$ - white
${\mathrm{PbCrO}}_4$ - yellow
$\mathrm{AgBr}$ - pale yellow
${\mathrm{PbI}}_2$ - yellow
${\mathrm{CaC}}_2{\mathrm{O}}_4$ - white

$\left[\mathrm{Fe}(\mathrm{OH}{)}_2\left({\mathrm{CH}}_3\mathrm{COO}\right)\right]$ – Brown Red

Hence the number of salts which are white in colour is $5$.