Q56 / 160 · TS EAMCET 2022 (19 Jul Shift 2) · Mathematics
The number of ways of arranging the letters of the word LINEAR so that the letters $\mathrm{N}$ and $\mathrm{R}$ do not come together and $\mathrm{E}$ and $\mathrm{A}$ come together is
- A80
- B60
- C10
- Correct answerD144
Solution
We have a word; LINEAR then no. of arrangements having EA together is

now an arrangement having RN and EA together is
Hence no. of words having $\mathrm{N}$ and $\mathrm{R}$ not together is $240-96=144$

now an arrangement having RN and EA together is

Hence no. of words having $\mathrm{N}$ and $\mathrm{R}$ not together is $240-96=144$
Hence, the correct answer is option: 'D'.