Q13 / 98 · NTA Abhyas (JEE Main) 2020 · Mathematics · Permutation Combination

The number of ways of arranging $8$ men and $4$ women around a circular table such that no two women can sit together, is

A
$8!$
B
$4!$
C
$8! 4!$
Correct answer
D
$7!^{8} P_{4}$

Solution

The number of ways of arranging

8

men

= 7!

The number of ways of arranging

4

women such that no two women can sit together

= {^{8} P}_{4}

∴

Required number of ways

= {7!}^{8} P_{4}

Hence, the correct answer is option: 'D'.

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