Q20 / 83 · NTA Abhyas (JEE Main) 2020 · Mathematics · Trigonometric Equations

The number of values of x in the interval 0,5π satisfying the equation 3sin2⁡x-7sin⁡x+2=0 is

  • A
    0
  • B
    5
  • Correct answer
    C
    6
  • D
    10

Solution

3sin2⁡x-7sin⁡x+2=0
3sin2⁡x-6sin⁡x-sin⁡x+2=0
3sin⁡x-1sin⁡x-2=0
⇒sin⁡x=13,sin⁡x=2 not possible
Figure
Fro the figure, 6 roots in 0,5π

Hence, the correct answer is option: 'C'.

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