Q100 / 180 · KCET 2020 · Mathematics
The number of terms in the expansion of $(x+y+z)^{10}$ is
- Correct answerA66
- B142
- C11
- D110
Solution
We have,
$(x+y+z)^{10}$
Total number of terms in the expansion of
$(x+y+z)^{10}={ }^{10+3-1} C_{3-1}={ }^{12} C_{2}=66$
Hence, the correct answer is option: 'A'.