Q100 / 180 · KCET 2020 · Mathematics

The number of terms in the expansion of $(x+y+z)^{10}$ is

  • Correct answer
    A
    66
  • B
    142
  • C
    11
  • D
    110

Solution

We have, $(x+y+z)^{10}$ Total number of terms in the expansion of $(x+y+z)^{10}={ }^{10+3-1} C_{3-1}={ }^{12} C_{2}=66$

Hence, the correct answer is option: 'A'.

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