Q63 / 120 · VITEEE 2007 · Mathematics

The number of positive integral solutions of the equation $x_{1} x_{2} x_{3} x_{4} x_{5}=1050$ is

  • A
    1870
  • Correct answer
    B
    1875
  • C
    1865
  • D
    1880

Solution

Given, $x_{1} x_{2} x_{3} x_{4} x_{5}=1050$ $\Rightarrow x_{1} x_{2} x_{3} x_{4} x_{5}=2 \times 3 \times 5^{2} \times 7$ Each of 2,3 or 7 can take 5 places and $5^{2}$ can be disposed in 15 ways. Hence, number of positive integral solution $=5^{3} \times 15=1875$

Hence, the correct answer is option: 'B'.

Relevant Questions